Как найти java path

I need to know where JDK is located on my machine.

On running Java -version in cmd, it shows the version as ‘1.6.xx’.
To find the location of this SDK on my machine I tried using echo %JAVA_HOME% but it is only showing ‘JAVA_HOME’ (as there is no ‘JAVA_PATH’ var set in my environment variables).

In windows the default is: C:Program FilesJavajdk1.6.0_14 (where the numbers may differ, as they’re the version).

Java installer puts several files into %WinDir%System32 folder (java.exe, javaws.exe and some others). When you type java.exe in command line or create process without full path, Windows runs these as last resort if they are missing in %PATH% folders.

You can lookup all versions of Java installed in registry. Take a look at HKLMSOFTWAREJavaSoftJava Runtime Environment and HKLMSOFTWAREWow6432NodeJavaSoftJava Runtime Environment for 32-bit java on 64 bit Windows.

This is how java itself finds out different versions installed. And this is why both 32-bit and 64-bit version can co-exist and works fine without interfering.

answered Feb 1, 2012 at 10:48

The batch script below will print out the existing default JRE. It can be easily modified to find the JDK version installed by replacing the Java Runtime Environment with Java Development Kit.

@echo off

setlocal

::- Get the Java Version
set KEY="HKLMSOFTWAREJavaSoftJava Runtime Environment"
set VALUE=CurrentVersion
reg query %KEY% /v %VALUE% 2>nul || (
    echo JRE not installed 
    exit /b 1
)
set JRE_VERSION=
for /f "tokens=2,*" %%a in ('reg query %KEY% /v %VALUE% ^| findstr %VALUE%') do (
    set JRE_VERSION=%%b
)

echo JRE VERSION: %JRE_VERSION%

::- Get the JavaHome
set KEY="HKLMSOFTWAREJavaSoftJava Runtime Environment%JRE_VERSION%"
set VALUE=JavaHome
reg query %KEY% /v %VALUE% 2>nul || (
    echo JavaHome not installed
    exit /b 1
)

set JAVAHOME=
for /f "tokens=2,*" %%a in ('reg query %KEY% /v %VALUE% ^| findstr %VALUE%') do (
    set JAVAHOME=%%b
)

echo JavaHome: %JAVAHOME%

endlocal

answered Aug 11, 2014 at 18:21

In Windows PowerShell you can use the Get-Command function to see where Java is installed:

Get-Command -All java

Or

gcm -All java

The -All part makes sure to show all places it appears in the Path lookup. Below is example output.

PS C:> gcm -All java

CommandType     Name                                               Version    Source
-----------     ----                                               -------    ------
Application     java.exe                                           8.0.202.8  C:Program Files (x86)Common FilesOracleJavajav...
Application     java.exe                                           8.0.131... C:ProgramDataOracleJavajavapathjava.exe

answered Nov 9, 2020 at 17:32

More on Windows… variable java.home is not always the same location as the binary that is run.

As Denis The Menace says, the installer puts Java files into Program Files, but also java.exe into System32. With nothing Java related on the path java -version can still work. However when PeterMmm’s program is run it reports the value of Program Files as java.home, this is not wrong (Java is installed there) but the actual binary being run is located in System32.

One way to hunt down the location of the java.exe binary, add the following line to PeterMmm’s code to keep the program running a while longer:

try{Thread.sleep(60000);}catch(Exception e) {}

Compile and run it, then hunt down the location of the java.exe image. E.g. in Windows 7 open the task manager, find the java.exe entry, right click and select ‘open file location’, this opens the exact location of the Java binary. In this case it would be System32.

answered Oct 24, 2012 at 10:23

Have you tried looking at your %PATH% variable. That’s what Windows uses to find any executable.

On macOS, run:

cd /tmp && echo 'public class Main {public static void main(String[] args) {System.out.println(System.getProperty("java.home"));}}' > Main.java && javac Main.java && java Main

On my machine, this prints:

/Library/Java/JavaVirtualMachines/jdk-9.0.4.jdk/Contents/Home

Note that running which java does not show the JDK location, because the java command is instead part of JavaVM.framework, which wraps the real JDK:

$ which java
/usr/bin/java
/private/tmp
$ ls -l /usr/bin/java
lrwxr-xr-x  1 root  wheel  74 14 Nov 17:37 /usr/bin/java -> /System/Library/Frameworks/JavaVM.framework/Versions/Current/Commands/java

answered Jan 18, 2018 at 13:58

None of these answers are correct for Linux if you are looking for the home that includes the subdirs such as: bin, docs, include, jre, lib, etc.

On Ubuntu for openjdk1.8.0, this is in:
/usr/lib/jvm/java-1.8.0-openjdk-amd64

and you may prefer to use that for JAVA_HOME since you will be able to find headers if you build JNI source files. While it’s true which java will provide the binary path, it is not the true JDK home.

answered Jan 27, 2016 at 1:33

I have improved munsingh’s answer above by testing for the registry key in 64-bit and 32-bit registries, if needed:

::- Test for the registry location  
SET VALUE=CurrentVersion
SET KEY_1="HKLMSOFTWAREJavaSoftJava Development Kit"
SET KEY_2=HKLMSOFTWAREJavaSoftJDK
SET REG_1=reg.exe
SET REG_2="C:Windowssysnativereg.exe"
SET REG_3="C:Windowssyswow64reg.exe"

SET KEY=%KEY_1%
SET REG=%REG_1%
%REG% QUERY %KEY% /v %VALUE% 2>nul
IF %ERRORLEVEL% EQU 0 GOTO _set_value

SET KEY=%KEY_2%
SET REG=%REG_1%
%REG% QUERY %KEY% /v %VALUE% 2>nul
IF %ERRORLEVEL% EQU 0 GOTO _set_value

::- %REG_2% is for 64-bit installations, using "C:Windowssysnative"
SET KEY=%KEY_1%
SET REG=%REG_2%
%REG% QUERY %KEY% /v %VALUE% 2>nul
IF %ERRORLEVEL% EQU 0 GOTO _set_value

SET KEY=%KEY_2%
SET REG=%REG_2%
%REG% QUERY %KEY% /v %VALUE% 2>nul
IF %ERRORLEVEL% EQU 0 GOTO _set_value

::- %REG_3% is for 32-bit installations on a 64-bit system, using "C:Windowssyswow64"
SET KEY=%KEY_1%
SET REG=%REG_3%
%REG% QUERY %KEY% /v %VALUE% 2>nul
IF %ERRORLEVEL% EQU 0 GOTO _set_value

SET KEY=%KEY_2%
SET REG=%REG_3%
%REG% QUERY %KEY% /v %VALUE% 2>nul
IF %ERRORLEVEL% EQU 0 GOTO _set_value

:_set_value
FOR /F "tokens=2,*" %%a IN ('%REG% QUERY %KEY% /v %VALUE%') DO (
    SET JDK_VERSION=%%b
)
SET KEY=%KEY%%JDK_VERSION%
SET VALUE=JavaHome
FOR /F "tokens=2,*" %%a IN ('%REG% QUERY %KEY% /v %VALUE%') DO (
    SET JAVAHOME=%%b
)
ECHO "%JAVAHOME%"
::- SETX JAVA_HOME "%JAVAHOME%"

reference for access to the 64-bit registry

answered Mar 28, 2018 at 17:51

Maybe the above methods work… I tried some and didn’t for me. What did was this :

Run this in terminal :

/usr/libexec/java_home

answered Oct 17, 2020 at 3:13

Simple method (Windows):
Open an application using java.
press ctrl + shift + esc

Right click on OpenJDK platform binary. Click open file location.
Then it will show java/javaw.exe then go to the top where it shows the folder and click on the jdk then right copy the path, boom. (Wont work for apps using bundled jre paths/runtimes, because it will show path to the bundled runtime)

Script for 32/64 bit Windows.

@echo off

setlocal enabledelayedexpansion

::- Get the Java Version
set KEY="HKLMSOFTWAREJavaSoftJava Runtime Environment"
set KEY64="HKLMSOFTWAREWOW6432NodeJavaSoftJava Runtime Environment"
set VALUE=CurrentVersion
reg query %KEY% /v %VALUE% 2>nul || (
    set KEY=!KEY64!
    reg query !KEY! /v %VALUE% 2>nul || (
    echo JRE not installed 
    exit /b 1
)
)

set JRE_VERSION=
for /f "tokens=2,*" %%a in ('reg query %KEY% /v %VALUE% ^| findstr %VALUE%') do (
    set JRE_VERSION=%%b
)

echo JRE VERSION: %JRE_VERSION%

::- Get the JavaHome
set KEY="HKLMSOFTWAREJavaSoftJava Runtime Environment%JRE_VERSION%"
set KEY64="HKLMSOFTWAREWOW6432NodeJavaSoftJava Runtime Environment%JRE_VERSION%"
set VALUE=JavaHome
reg query %KEY% /v %VALUE% 2>nul || (
    set KEY=!KEY64!
    reg query !KEY! /v %VALUE% 2>nul || (
    echo JavaHome not installed
    exit /b 1
)
)

set JAVAHOME=
for /f "tokens=2,*" %%a in ('reg query %KEY% /v %VALUE% ^| findstr %VALUE%') do (
    set JAVAHOME=%%b
)

echo JavaHome: %JAVAHOME%

endlocal

answered Mar 26, 2019 at 23:23

In Windows 7, right-click on Computer -> Properties -> Advanced system settings; then in the Advanced tab, click Environment Variables… -> System variables -> New….

Give the new system variable the name JAVA_HOME and the value C:Program FilesJavajdk1.7.0_79 (depending on your JDK installation path it varies).

Then select the Path system variable and click Edit…. Keep the variable name as Path, and append C:Program FilesJavajdk1.7.0_79bin; or %JAVA_HOME%bin; (both mean the same) to the variable value.

Once you are done with above changes, try below steps. If you don’t see similar results, restart the computer and try again. If it still doesn’t work you may need to reinstall JDK.

Open a Windows command prompt (Windows key + R -> enter cmd -> OK), and check the following:

java -version

You will see something like this:

java version "1.7.0_79"
Java(TM) SE Runtime Environment (build 1.7.0_79-b15)
Java HotSpot(TM) 64-Bit Server VM (build 24.79-b02, mixed mode)

Then check the following:

javac -version

You will see something like this:

javac 1.7.0_79

answered Nov 4, 2015 at 3:43

I am going to explain here by pictures for Windows 7.

Please follow the following steps:

Step 1:
Go to «Start» and get into the «My Computer» properties

Step 2: Go to «Advance System Setting» and click on it.

Step 3: Go to «Start» and get into the «My Computer» properties

Step 4: The dialog for Environment variable will open like this:

Step 5: Go to path and click on edit.

Step 6: Put the path of your JDK wherever it resides up to bin like you can see in the picture. Also add path from your sdk of Android up to the Platform Tools:

answered Jul 10, 2015 at 12:10

For Windows 7 users:

Right-click on My Computer, select Properties; Advanced; System Settings; Advanced; Environment Variables. Then find PATH in the second box and set the variable like in the picture below.

Java path set for java 11

1. copy the path for jdk-11

Don’t include the bin folder, just the JDK path. For example

Correct – C:Program FilesJavajdk-11

Wrong – C:Program FilesJavajdk-11bin

In environmental variable, user variable section click on New button and give path like below.

after that give ok for it and go to the System variables and select the Path and double click on it.

click on new and paste %JAVA_HOME%bin and click ok to all.

answered May 6, 2021 at 22:10

For deployment better to set up classpath exactly and keep environment clear.
Or at *.bat (the same for linux, but with correct variables symbols):

CLASSPATH="c:lib;d:temptest.jar;<long classpath>"
CLASSPATH=%CLASSPATH%;"<another_logical_droup_of_classpath" 
java -cp %CLASSPATH% com.test.MainCLass

Or at command line or *.bat (for *.sh too) if classpath id not very long:

java -cp "c:lib;d:temptest.jar;<short classpath>"

answered Nov 4, 2009 at 8:26

For Windows:

• Right click on ‘My Computers’ and open ‘Properties’.
• In Windows Vista or Windows 7, go to «Advanced System Settings». Else go to next step.
• Go to ‘Advanced Tab’ and click on Environment Variables button.
• Select ‘Path’ under the list of ‘System Variables’, and press Edit and add C:Program Filesjavajdkbin after a semicolon.
• Now click on ‘new’ button under system variables and enter ‘JAVA_HOME’ as variable name and path to jdk home directory (ex. ‘C:Program FilesJavajdk1.6.0_24’ if you are installing java version 6. Directory name may change with diff. java versions) as variable_value.

answered Sep 6, 2013 at 11:14

1. Download the JDK
2. Install it
3. Then Setup environment variables like this :
4. Click on EDIT

1. Then click PATH, Click Add , Then Add it like this:
   

answered May 16, 2019 at 11:04

answered Aug 9, 2021 at 17:35

You can add JAVA_HOME in the system environment variable from my computer>>advance tab>add the new path as explained here.

It might help Mac and Linux users as well.

answered Jun 12, 2022 at 5:14

asked May 14, 2016 at 10:29

Simply do (in terminal):

update-alternatives --list java

And you’ll get an output like this:

 $ update-alternatives --list java
/usr/bin/gij-5
/usr/lib/jvm/java-8-openjdk-amd64/jre/bin/java

The last line is the place your java is in.

Starting from January 2019, the licensing model for Oracle Java has changed. PPAs such as ‘ppa:webupd8team/java’ used in many Java installation tutorials now become unavailable.

Here I would like to share how I installed Java 8 on Ubuntu 16.04, and set the Java path in terminal.

Installation

Reference: https://java.com/en/download/help/linux_x64_install.xml

I followed the instruction on the official documentation to install Java with .tar.gz

Path setting

Reference: https://java.com/en/download/help/path.xml

The instruction is also from the official documentations. The steps to set up Java path are much simpler here.

After performing all the steps, restart the terminal and run ‘java -version’ to verify installation.

answered Aug 15, 2019 at 3:03