Как найти номер строки sql

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ROW_NUMBER (Transact-SQL)

Transact-SQL reference for the ROW_NUMBER function. This function numbers the output of a result set.

MikeRayMSFT

mikeray

09/11/2017

sql

t-sql

reference

ROW_NUMBER

ROW_NUMBER_TSQL

ROW_NUMBER()_TSQL

ROW_NUMBER function

row numbers [SQL Server]

sequential row numbers [SQL Server]

TSQL

>= aps-pdw-2016 || = azuresqldb-current || = azure-sqldw-latest || >= sql-server-2016 || >= sql-server-linux-2017 || = azuresqldb-mi-current||=fabric

ROW_NUMBER (Transact-SQL)

[!INCLUDE sql-asdb-asdbmi-asa-pdw-fabricse-fabricdw]

Numbers the output of a result set. More specifically, returns the sequential number of a row within a partition of a result set, starting at 1 for the first row in each partition.

ROW_NUMBER and RANK are similar. ROW_NUMBER numbers all rows sequentially (for example 1, 2, 3, 4, 5). RANK provides the same numeric value for ties (for example 1, 2, 2, 4, 5).

[!NOTE]
ROW_NUMBER is a temporary value calculated when the query is run. To persist numbers in a table, see IDENTITY Property and SEQUENCE.

:::image type=»icon» source=»../../includes/media/topic-link-icon.svg» border=»false»::: Transact-SQL syntax conventions

Syntax

ROW_NUMBER ( )   
    OVER ( [ PARTITION BY value_expression , ... [ n ] ] order_by_clause )  

[!INCLUDEsql-server-tsql-previous-offline-documentation]

Arguments

PARTITION BY value_expression
Divides the result set produced by the FROM clause into partitions to which the ROW_NUMBER function is applied. value_expression specifies the column by which the result set is partitioned. If PARTITION BY is not specified, the function treats all rows of the query result set as a single group. For more information, see OVER Clause (Transact-SQL).

order_by_clause
The ORDER BY clause determines the sequence in which the rows are assigned their unique ROW_NUMBER within a specified partition. It is required. For more information, see OVER Clause (Transact-SQL).

Return Types

bigint

General Remarks

There is no guarantee that the rows returned by a query using ROW_NUMBER() will be ordered exactly the same with each execution unless the following conditions are true.

  1. Values of the partitioned column are unique.

  2. Values of the ORDER BY columns are unique.

  3. Combinations of values of the partition column and ORDER BY columns are unique.

ROW_NUMBER() is nondeterministic. For more information, see Deterministic and Nondeterministic Functions.

Examples

A. Simple examples

The following query returns the four system tables in alphabetic order.

SELECT 
  name, recovery_model_desc
FROM sys.databases 
WHERE database_id < 5
ORDER BY name ASC;

[!INCLUDEssResult]

name recovery_model_desc
master SIMPLE
model FULL
msdb SIMPLE
tempdb SIMPLE

To add a row number column in front of each row, add a column with the ROW_NUMBER function, in this case named Row#. You must move the ORDER BY clause up to the OVER clause.

SELECT 
  ROW_NUMBER() OVER(ORDER BY name ASC) AS Row#,
  name, recovery_model_desc
FROM sys.databases 
WHERE database_id < 5;

[!INCLUDEssResult]

Row# name recovery_model_desc
1 master SIMPLE
2 model FULL
3 msdb SIMPLE
4 tempdb SIMPLE

Adding a PARTITION BY clause on the recovery_model_desc column, will restart the numbering when the recovery_model_desc value changes.

SELECT 
  ROW_NUMBER() OVER(PARTITION BY recovery_model_desc ORDER BY name ASC) 
    AS Row#,
  name, recovery_model_desc
FROM sys.databases WHERE database_id < 5;

[!INCLUDEssResult]

Row# name recovery_model_desc
1 model FULL
1 master SIMPLE
2 msdb SIMPLE
3 tempdb SIMPLE

B. Returning the row number for salespeople

The following example calculates a row number for the salespeople in [!INCLUDEssSampleDBCoFull] based on their year-to-date sales ranking.

USE AdventureWorks2012;   
GO  
SELECT ROW_NUMBER() OVER(ORDER BY SalesYTD DESC) AS Row,   
    FirstName, LastName, ROUND(SalesYTD,2,1) AS "Sales YTD"   
FROM Sales.vSalesPerson  
WHERE TerritoryName IS NOT NULL AND SalesYTD <> 0;  

[!INCLUDEssResult]

  
Row FirstName    LastName               SalesYTD  
--- -----------  ---------------------- -----------------  
1   Linda        Mitchell               4251368.54  
2   Jae          Pak                    4116871.22  
3   Michael      Blythe                 3763178.17  
4   Jillian      Carson                 3189418.36  
5   Ranjit       Varkey Chudukatil      3121616.32  
6   José         Saraiva                2604540.71  
7   Shu          Ito                    2458535.61  
8   Tsvi         Reiter                 2315185.61  
9   Rachel       Valdez                 1827066.71  
10  Tete         Mensa-Annan            1576562.19  
11  David        Campbell               1573012.93  
12  Garrett      Vargas                 1453719.46  
13  Lynn         Tsoflias               1421810.92  
14  Pamela       Ansman-Wolfe           1352577.13  

C. Returning a subset of rows

The following example calculates row numbers for all rows in the SalesOrderHeader table in the order of the OrderDate and returns only rows 50 to 60 inclusive.

USE AdventureWorks2012;  
GO  
WITH OrderedOrders AS  
(  
    SELECT SalesOrderID, OrderDate,  
    ROW_NUMBER() OVER (ORDER BY OrderDate) AS RowNumber  
    FROM Sales.SalesOrderHeader   
)   
SELECT SalesOrderID, OrderDate, RowNumber    
FROM OrderedOrders   
WHERE RowNumber BETWEEN 50 AND 60;  

D. Using ROW_NUMBER() with PARTITION

The following example uses the PARTITION BY argument to partition the query result set by the column TerritoryName. The ORDER BY clause specified in the OVER clause orders the rows in each partition by the column SalesYTD. The ORDER BY clause in the SELECT statement orders the entire query result set by TerritoryName.

USE AdventureWorks2012;  
GO  
SELECT FirstName, LastName, TerritoryName, ROUND(SalesYTD,2,1) AS SalesYTD,  
ROW_NUMBER() OVER(PARTITION BY TerritoryName ORDER BY SalesYTD DESC) 
  AS Row  
FROM Sales.vSalesPerson  
WHERE TerritoryName IS NOT NULL AND SalesYTD <> 0  
ORDER BY TerritoryName;  

[!INCLUDEssResult]

  
FirstName  LastName             TerritoryName        SalesYTD      Row  
---------  -------------------- ------------------   ------------  ---  
Lynn       Tsoflias             Australia            1421810.92    1  
José       Saraiva              Canada               2604540.71    1  
Garrett    Vargas               Canada               1453719.46    2  
Jillian    Carson               Central              3189418.36    1  
Ranjit     Varkey Chudukatil    France               3121616.32    1  
Rachel     Valdez               Germany              1827066.71    1  
Michael    Blythe               Northeast            3763178.17    1  
Tete       Mensa-Annan          Northwest            1576562.19    1  
David      Campbell             Northwest            1573012.93    2  
Pamela     Ansman-Wolfe         Northwest            1352577.13    3  
Tsvi       Reiter               Southeast            2315185.61    1  
Linda      Mitchell             Southwest            4251368.54    1  
Shu        Ito                  Southwest            2458535.61    2  
Jae        Pak                  United Kingdom       4116871.22    1  

Examples: [!INCLUDEssazuresynapse-md] and [!INCLUDEssPDW]

E. Returning the row number for salespeople

The following example returns the ROW_NUMBER for sales representatives based on their assigned sales quota.

-- Uses AdventureWorks  
  
SELECT ROW_NUMBER() OVER(ORDER BY SUM(SalesAmountQuota) DESC) 
    AS RowNumber,  
    FirstName, LastName,   
    CONVERT(varchar(13), SUM(SalesAmountQuota),1) AS SalesQuota   
FROM dbo.DimEmployee AS e  
INNER JOIN dbo.FactSalesQuota AS sq  
    ON e.EmployeeKey = sq.EmployeeKey  
WHERE e.SalesPersonFlag = 1  
GROUP BY LastName, FirstName;  

Here is a partial result set.


RowNumber  FirstName  LastName            SalesQuota  
---------  ---------  ------------------  -------------  
1          Jillian    Carson              12,198,000.00  
2          Linda      Mitchell            11,786,000.00  
3          Michael    Blythe              11,162,000.00  
4          Jae        Pak                 10,514,000.00  

F. Using ROW_NUMBER() with PARTITION

The following example shows using the ROW_NUMBER function with the PARTITION BY argument. This causes the ROW_NUMBER function to number the rows in each partition.

-- Uses AdventureWorks  
  
SELECT ROW_NUMBER() OVER(PARTITION BY SalesTerritoryKey 
        ORDER BY SUM(SalesAmountQuota) DESC) AS RowNumber,  
    LastName, SalesTerritoryKey AS Territory,  
    CONVERT(varchar(13), SUM(SalesAmountQuota),1) AS SalesQuota   
FROM dbo.DimEmployee AS e  
INNER JOIN dbo.FactSalesQuota AS sq  
    ON e.EmployeeKey = sq.EmployeeKey  
WHERE e.SalesPersonFlag = 1  
GROUP BY LastName, FirstName, SalesTerritoryKey;  

Here is a partial result set.

 
RowNumber  LastName            Territory  SalesQuota  
---------  ------------------  ---------  -------------  
1          Campbell            1           4,025,000.00  
2          Ansman-Wolfe        1           3,551,000.00  
3          Mensa-Annan         1           2,275,000.00  
1          Blythe              2          11,162,000.00  
1          Carson              3          12,198,000.00  
1          Mitchell            4          11,786,000.00  
2          Ito                 4           7,804,000.00  

See Also

RANK (Transact-SQL)
DENSE_RANK (Transact-SQL)
NTILE (Transact-SQL)

Summary: in this tutorial, you will learn how to use the ROW_NUMBER() to assign a sequential number to each row in a query result set.

SQL ROW_NUMBER() Function Overview

The ROW_NUMBER() is a window function that assigns a sequential integer number to each row in the query’s result set.

The following illustrates the syntax of the ROW_NUMBER() function:

ROW_NUMBER() OVER ( [PARTITION BY expr1, expr2,...] ORDER BY expr1 [ASC | DESC], expr2,... )

Code language: SQL (Structured Query Language) (sql)

In this syntax,

  • First, the PARTITION BY clause divides the result set returned from the FROM clause into partitions. The PARTITION BY clause is optional. If you omit it, the whole result set is treated as a single partition.
  • Then, the ORDER BY clause sorts the rows in each partition. Because the ROW_NUMBER() is an order sensitive function, the ORDER BY clause is required.
  • Finally, each row in each partition is assigned a sequential integer number called a row number. The row number is reset whenever the partition boundary is crossed.

SQL ROW_NUMBER() examples

We will use the employees and departments tables from the sample database for the demonstration:

Employees & Departments Tables

A) Simple SQL ROW_NUMBER() example

The following statement finds the first name, last name, and salary of all employees. In addition, it uses the ROW_NUMBER() function to add sequential integer number to each row.

SELECT ROW_NUMBER() OVER ( ORDER BY salary ) row_num, first_name, last_name, salary FROM employees;

Code language: SQL (Structured Query Language) (sql)

The following picture shows the partial result set:

SQL ROW_NUMBER Function Example

B) Using SQL ROW_NUMBER() for pagination

The ROW_NUMBER() function can be used for pagination. For example, if you want to display all employees on a table in an application by pages, which each page has ten records.

  • First, use the ROW_NUMBER() function to assign each row a sequential integer number.
  • Second, filter rows by requested page. For example, the first page has the rows starting from one to 9, and the second page has the rows starting from 11 to 20, and so on.

The following statement returns the records of the second page, each page has ten records.

-- pagination get page #2 SELECT * FROM ( SELECT ROW_NUMBER() OVER (ORDER BY salary) row_num, first_name, last_name, salary FROM employees ) t WHERE row_num > 10 AND row_num <=20;

Code language: SQL (Structured Query Language) (sql)

The following shows the output:

SQL ROW_NUMBER Function - Pagination Example

If you want to use the common table expression (CTE) instead of the subquery, here is the query:

WITH t AS( SELECT ROW_NUMBER() OVER ( ORDER BY salary ) row_num, first_name, last_name, salary FROM employees ) SELECT * FROM t WHERE row_num > 10 AND row_num <=20;

Code language: SQL (Structured Query Language) (sql)

C) Using SQL ROW_NUMBER() for finding nth highest value per group

The following example shows you how to find the employees whose have the highest salary in their departments:

-- find the highest salary per department SELECT department_name, first_name, last_name, salary FROM ( SELECT department_name, `ROW_NUMBER()` OVER ( PARTITION BY department_name ORDER BY salary DESC) row_num, first_name, last_name, salary FROM employees e INNER JOIN departments d ON d.department_id = e.department_id ) t WHERE row_num = 1;

Code language: SQL (Structured Query Language) (sql)

In the subquery:

  • First, the PARTITION BY clause distributes the employees by departments.
  • Second, the ORDER BY clause sorts the employee in each department by salary in the descending order.
  • Third, the ROW_NUMBER() assigns each row a sequential integer number. It resets the number when the department changes.

The following shows the result set of the subquery:

SQL ROW_NUMBER Function - subquery

In the outer query, we selected only the employee rows which have the row_num with the value 1.

Here is the output of the whole query:

SQL ROW_NUMBER Function - find nth value per group

If you change the predicate in the WHERE clause from 1 to 2, 3, and so on, you will get the employees who have the second highest salary, third highest salary, and so on.

In this tutorial, you have learned how to use the SQL ROW_NUMBER() function to assign a sequential integer number to each row in the result set of a query.

Was this tutorial helpful ?

Can I run a select statement and get the row number if the items are sorted?

I have a table like this:

mysql> describe orders;
+-------------+---------------------+------+-----+---------+----------------+
| Field       | Type                | Null | Key | Default | Extra          |
+-------------+---------------------+------+-----+---------+----------------+
| orderID     | bigint(20) unsigned | NO   | PRI | NULL    | auto_increment |
| itemID      | bigint(20) unsigned | NO   |     | NULL    |                |
+-------------+---------------------+------+-----+---------+----------------+

I can then run this query to get the number of orders by ID:

SELECT itemID, COUNT(*) as ordercount
FROM orders
GROUP BY itemID ORDER BY ordercount DESC;

This gives me a count of each itemID in the table like this:

+--------+------------+
| itemID | ordercount |
+--------+------------+
|    388 |          3 |
|    234 |          2 |
|   3432 |          1 |
|    693 |          1 |
|   3459 |          1 |
+--------+------------+

I want to get the row number as well, so I could tell that itemID=388 is the first row, 234 is second, etc (essentially the ranking of the orders, not just a raw count). I know I can do this in Java when I get the result set back, but I was wondering if there was a way to handle it purely in SQL.

Update

Setting the rank adds it to the result set, but not properly ordered:

mysql> SET @rank=0;
Query OK, 0 rows affected (0.00 sec)

mysql> SELECT @rank:=@rank+1 AS rank, itemID, COUNT(*) as ordercount
    -> FROM orders
    -> GROUP BY itemID ORDER BY rank DESC;
+------+--------+------------+
| rank | itemID | ordercount |
+------+--------+------------+
|    5 |   3459 |          1 |
|    4 |    234 |          2 |
|    3 |    693 |          1 |
|    2 |   3432 |          1 |
|    1 |    388 |          3 |
+------+--------+------------+
5 rows in set (0.00 sec)

Consider example table below

ProductDetailNo    ProductDescription
      224                Apples
      225                Tomatoes
      226                Potatoes

How do I list the row number for a selected row like below ?

RowNo    ProductDetailNo          Product Description
  2         225                Tomatoes

Using row_number() in my query just returns 1 always for a single record no mater what the logical row is in the database.

Thanks, Damien.

asked Jan 5, 2012 at 7:02

Zo Has's user avatar

5

try this

WITH MyTable AS
(
    SELECT ProductDetailNo, ProductDescription,
    ROW_NUMBER() OVER ( ORDER BY ProductDetailNo ) AS 'RowNumber'
    FROM Product
) 
SELECT RowNumber, ProductDetailNo     
FROM MyTable 
WHERE ProductDetailNo = 225

Hakan Fıstık's user avatar

Hakan Fıstık

16.5k13 gold badges107 silver badges130 bronze badges

answered Jan 5, 2012 at 7:07

Shoaib Shaikh's user avatar

Shoaib ShaikhShoaib Shaikh

4,5651 gold badge26 silver badges35 bronze badges

6

Please Check This

WITH ArticleSearch AS
    (
        SELECT
            ROW_NUMBER() OVER 
                (
                    ORDER BY tblProducts.ProductDetailNo                                    
                ) AS RowNumber, 
            tblProducts.ProductDetailNo, 
            tblProducts.ProductDescription    
        FROM         
            tblProducts
    )

    SELECT 
        a.RowNumber AS SlNo,
        a.ProductDetailNo,
        a.ProductDescription
    FROM
          ArticleSearch a
    WHERE
          a.ProductDetailNo=225

answered Jan 5, 2012 at 7:22

Renju Vinod's user avatar

Renju VinodRenju Vinod

2541 gold badge3 silver badges11 bronze badges

1

What about this one?

SELECT RowNo, ProductDetailNo, ProductDescription
FROM (SELECT ROW_NUMBER() as RowNo, ProductDetailNo, ProductDescription
      FROM TheTable) as t
WHERE ProductDetailNo = 225;

answered Jan 5, 2012 at 7:09

Sergio Tulentsev's user avatar

Sergio TulentsevSergio Tulentsev

226k43 gold badges370 silver badges364 bronze badges

4

  WITH productCTE 
  AS
  (SELECT ROW_NUMBER() OVER(ORDER BY ProductDetailNo, ProductDescription) AS RowNo, ProductDetailNo, ProductDescription
   FROM tbl_Products
  )
  SELECT * FROM productCTE
  WHERE RowNo = 2

musefan's user avatar

musefan

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answered Jan 5, 2012 at 9:04

Gopu's user avatar

GopuGopu

559 bronze badges

The row number you receive is from number of the rows of result. i.e. if your result has just one tuple, the row no. will always be 1.

To get row number of the entire table, you should add a extra attribute, a RowNo with auto increment to your table.

Hope this helps, but possibly SQL has even better solution for you!

answered Jan 5, 2012 at 7:07

Vinayak Garg's user avatar

Vinayak GargVinayak Garg

6,51810 gold badges53 silver badges80 bronze badges

1

There is no inherent row number for a table row. ROW_NUMBER() gives you the number of the row only within a specific result set. So it is the expected result that you always get 1 when the result set contains only 1 record. If you want a row number, your table schema should include something like an auto-incrementing IDENTITY column.

answered Jan 5, 2012 at 7:09

bobbymcr's user avatar

bobbymcrbobbymcr

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1

The MySQL ROW_NUMBER() function returns the row number of the current row within the partition where the current row is located, starting from 1.

ROW_NUMBER() Syntax

Here is the syntax of the MySQL ROW_NUMBER() function:

ROW_NUMBER()
OVER (
  [PARTITION BY partition_column_list]
  [ORDER BY order_column_list]
)

Parameters

partition_column_list

List of columns for partitioning.

partition_column_list

List of columns for sorting.

Return value

The MySQL ROW_NUMBER() function returns the row number of the current row within the partition where the current row is located, starting from 1.

ROW_NUMBER() Examples

Preparing Data

Use the following CREATE TABLE statement to create a table named student_grade to store grades of students:

CREATE TABLE student_grade (
  id INT AUTO_INCREMENT PRIMARY KEY,
  name VARCHAR(50) NOT NULL,
  class CHAR(1) NOT NULL,
  subject VARCHAR(20) NOT NULL,
  grade INT NOT NULL
);

This student_grade table has 5 columns as following:

  • id — The row ID, primary key.
  • name — The name of a student.
  • class — The class a student is in.
  • subject — The name of a subject.
  • grade — The grades for a subject and a student.

Insert some rows into the student_grade table using the following INSERT statement:

INSERT INTO student_grade
  (name, class, subject, grade)
VALUES
  ('Tim', 'A', 'Math', 9),
  ('Tom', 'A', 'Math', 7),
  ('Jim', 'A', 'Math', 8),
  ('Tim', 'A', 'English', 7),
  ('Tom', 'A', 'English', 8),
  ('Jim', 'A', 'English', 7),
  ('Lucy', 'B', 'Math', 8),
  ('Jody', 'B', 'Math', 6),
  ('Susy', 'B', 'Math', 9),
  ('Lucy', 'B', 'English', 6),
  ('Jody', 'B', 'English', 7),
  ('Susy', 'B', 'English', 8);

Use the following SELECT statement to show all rows in this table:

SELECT * FROM student_grade;
+----+------+-------+---------+-------+
| id | name | class | subject | grade |
+----+------+-------+---------+-------+
|  1 | Tim  | A     | Math    |     9 |
|  2 | Tom  | A     | Math    |     7 |
|  3 | Jim  | A     | Math    |     8 |
|  4 | Tim  | A     | English |     7 |
|  5 | Tom  | A     | English |     8 |
|  6 | Jim  | A     | English |     7 |
|  7 | Lucy | B     | Math    |     8 |
|  8 | Jody | B     | Math    |     6 |
|  9 | Susy | B     | Math    |     9 |
| 10 | Lucy | B     | English |     6 |
| 11 | Jody | B     | English |     7 |
| 12 | Susy | B     | English |     8 |
+----+------+-------+---------+-------+
12 rows in set (0.00 sec)

Example 1

To show the row number of each student in each subject in descending order of grade, use the following statement:

SELECT *,
  ROW_NUMBER() OVER (
    PARTITION BY subject
    ORDER BY grade DESC
  ) "row_number"
FROM student_grade;
+----+------+-------+---------+-------+------------+
| id | name | class | subject | grade | ROW_NUMBER |
+----+------+-------+---------+-------+------------+
|  5 | Tom  | A     | English |     8 |          1 |
| 12 | Susy | B     | English |     8 |          2 |
|  4 | Tim  | A     | English |     7 |          3 |
|  6 | Jim  | A     | English |     7 |          4 |
| 11 | Jody | B     | English |     7 |          5 |
| 10 | Lucy | B     | English |     6 |          6 |
|  1 | Tim  | A     | Math    |     9 |          1 |
|  9 | Susy | B     | Math    |     9 |          2 |
|  3 | Jim  | A     | Math    |     8 |          3 |
|  7 | Lucy | B     | Math    |     8 |          4 |
|  2 | Tom  | A     | Math    |     7 |          5 |
|  8 | Jody | B     | Math    |     6 |          6 |
+----+------+-------+---------+-------+------------+
12 rows in set (0.00 sec)

Note that the window function in the SQL statement above:

ROW_NUMBER() OVER (
  PARTITION BY subject
  ORDER BY grade DESC
)

In the OVER clause,

  • The PARTITION BY subject partitions all rows by subject
  • The ORDER BY grade sorts all rows within each partition in ascending order by grade.
  • The ROW_NUMBER() returns the row number of each row within its associated partition.

Example 2

To show the row number of each student in each class in descending order of total grade, use the following statement:

SELECT t.*,
  ROW_NUMBER() OVER (
    PARTITION BY class
    ORDER BY t.sum_grade DESC
  ) "row_number"
FROM (
    SELECT class,
      name,
      sum(grade) sum_grade
    FROM student_grade
    GROUP BY class, name
  ) t;
+-------+------+-----------+------------+
| class | name | sum_grade | ROW_NUMBER |
+-------+------+-----------+------------+
| A     | Tim  |        16 |          1 |
| A     | Tom  |        15 |          2 |
| A     | Jim  |        15 |          3 |
| B     | Susy |        17 |          1 |
| B     | Lucy |        14 |          2 |
| B     | Jody |        13 |          3 |
+-------+------+-----------+------------+
6 rows in set (0.00 sec)

Notice this subquery in the above statement:

SELECT class,
  name,
  sum(grade) sum_grade
FROM student_grade
GROUP BY class, name

This subquery uses the GROUP BY clause and the sum() function sums up each student’s total grade by class and student.

+-------+------+-----------+
| class | name | sum_grade |
+-------+------+-----------+
| A     | Tim  |        16 |
| A     | Tom  |        15 |
| A     | Jim  |        15 |
| B     | Lucy |        14 |
| B     | Jody |        13 |
| B     | Susy |        17 |
+-------+------+-----------+
6 rows in set (0.01 sec)

The main statement partitions all rows from this subquery by classes, then sort by total grade in descending order within each partition, and gets the row number of each row within its associated partition using ROW_NUMBER().

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