Как найти последнюю цифру числа java

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Последняя цифра числа равна остатку от деления на 10, lastCharacter = count%10

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I need to define the last digit of a number assign this to value.
After this, return the last digit.

My snippet of code doesn’t work correctly…

Code:

public int lastDigit(int number) {
    String temp = Integer.toString(number);
    int[] guess = new int[temp.length()];
    int last = guess[temp.length() - 1];

    return last;
}

Question:

• How to solve this issue?

asked Jun 17, 2013 at 10:08

Use

int lastDigit = number % 10. 

Read about Modulo operator: http://en.wikipedia.org/wiki/Modulo_operation

Or, if you want to go with your String solution

String charAtLastPosition = temp.charAt(temp.length()-1);

answered Jun 17, 2013 at 10:13

No need to use any strings.Its over burden.

int i = 124;
int last= i%10;
System.out.println(last);   //prints 4

answered Jun 17, 2013 at 10:11

answered Jun 17, 2013 at 10:10

Your array don’t have initialization. So it will give default value Zero.
You can try like this also

String temp = Integer.toString(urNumber);
System.out.println(temp.charAt(temp.length()-1));

answered Jun 17, 2013 at 10:48

public static void main(String[] args) {

    System.out.println(lastDigit(2347));
}

public static int lastDigit(int number)
{
    //your code goes here. 
    int last = number % 10;

    return last;
}

0/p:

7

Use StringUtils, in case you need string result:

String last = StringUtils.right(number.toString(), 1);

answered Jun 21, 2017 at 7:43

Another interesting way to do it which would also allow more than just the last number to be taken would be:

int number = 124454;
int overflow = (int)Math.floor(number/(1*10^n))*10^n;

int firstDigits = number - overflow;
//Where n is the number of numbers you wish to conserve</code>

In the above example if n was 1 then the program would return: 4

If n was 3 then the program would return 454

answered Dec 6, 2017 at 1:37

here is your method

public int lastDigit(int number)
{
    //your code goes here. 
    int last =number%10;
    return last;
}

Although the best way to do this is to use % if you insist on using strings this will work

public int lastDigit(int number)
{
return Integer.parseInt(String.valueOf(Integer.toString(number).charAt(Integer.toString(number).length() - 1)));
}

but I just wrote this for completeness. Do not use this code. it is just awful.

answered Jan 2, 2017 at 20:14