Как найти сумму чисел фибоначчи python

I am trying to implement the total sum of N whole numbers in Fibonacci

def fibo(n):
    if n<2:
        return 1
    else:
        res = fibo(n-1) + fibo(n-2)
        sum = sum + res
        return res, sum

n=7
sum = 0
for i in range(1, n):
    print(fibo(i))

print("Suma", sum)

#example: if n=7 then print : 1,1,2,3,5,8,13 and sum is 32

The error I have is, when I put sum = sum + res
Doesnt print & run the program

Currently, how could you implement the total sum?

rafaelc's user avatar

rafaelc

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asked Sep 24, 2018 at 21:16

Diego's user avatar

8

You simply need to calculate sum in the for loop, not in the fibo(n).
Here take a look:

def fibo(n):
if n<2:
    return 1
else:
    res = fibo(n-1) + fibo(n-2)
    return res

n=7
sum = 0
for i in range(0, n):
    r = fibo(i)
    sum += r
    print(r)

print("Suma", sum)

I used r in order to call fibo once in each loop.

answered Sep 24, 2018 at 21:59

AGGELOS's user avatar

Let me first point out that the sum of the first 7 terms of the Fibonacci sequence is not 32. That sum is 33. Now to the problem. Here is how I would solve the problem. I would first define the function that calculates the n th term of the Fibonacci sequence as follows:

def fibo(n):
    if n in [1,2]:
        return 1
    else:
        res = fibo(n-1) + fibo(n-2)
    return res

Then I would define a function to calculate the sum of the first n terms of the Fibonacci sequence as follows.

def sum_fibo(n):
    res = [fibo(i) for i in range(1, n+1)]
    print(res)
    return sum(res)

So if I do

[In] sum_fibo(7)

I get

        [1, 1, 2, 3, 5, 8, 13]
out >>> 33

NOTE: In defining the functions above, I have assumed that the input of the function is always going to be a positive integer though the Fibonacci can be extended to cover all real and complex numbers as shown on this wiki page.

answered Sep 24, 2018 at 22:23

Samuel Nde's user avatar

Samuel NdeSamuel Nde

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actually i don’t think this needs to be that complicated the fibonacci sequence is very interesting in a maltitude of ways for example, if you want the sum up the 7th fibonacci number, then have checked what the 9th fibonacci number — 1 is? Now how do we find the n’th fibonacci number?

p = (1+5**.5)/2
q = (1-5**.5)/2
def fibo(n):
    return 1/5**.5*(p**n-q**n)

and now we can can find the sum up to any number in one calculation! for example for 7

fibo(9)- 1

output

33

and what is the actual answer

1+1+2+3+5+8+13=33

summa summarum: the fibonachi number that is two places further down the sequence minus 1 is the sum of the fibonachi numbers up to the number

answered Sep 24, 2018 at 22:24

Jonas Wolff's user avatar

Jonas WolffJonas Wolff

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1

def sumOfNFibonacciNumbers(n):

# Write your code here
i = 1
sum = 2
fib_list = [0, 1, 1]
if n == 1:
    return 0
if n == 2:
    return 1
if n == 3:
    return 2
for x in range(1,n-2):
    m = fib_list[-1] + fib_list[-2]
    fib_list.append(m)
    sum = sum + m
return sum

result = sumOfNFibonacciNumbers(10)
print(result)

answered Oct 26, 2020 at 9:48

Aravinth Ponnusamy's user avatar

2

Made some modifications to your code:

def fibo(n):
    print(1)
    counter = 1
    old_num = 0
    new_num = 1
    sum_fib = 1
    while counter < n:
        fib = old_num + new_num
        print(fib)

        if counter < n:
            old_num = new_num
            new_num = fib
            sum_fib = sum_fib + fib
            counter = counter + 1

    print('sum:' + str(sum_fib))


#fibo(5)

answered Sep 24, 2018 at 21:51

SmitM's user avatar

SmitMSmitM

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2

First of all, the line sum = sum + res makes no sense because you never defined sum in the first place.

So, your function should look like

def fibo(n):
    if n<2:
        return 1
    else:
        return fibo(n-1) + fibo(n-2)

Second, you can get the sum by simply

sum_ = 0
for i in range(0, n):
    sum_ += fibo(i)

Or maybe

sum_ = sum(fibo(i) for i in range(0, n))

Notice that the latter would only work if you have not overridden the built-in function named sum

answered Sep 24, 2018 at 21:59

rafaelc's user avatar

rafaelcrafaelc

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You are referring the variable sum before assignment.

You may want to use the variable sum inside the for loop and assign the fibo to it.

    def fibo(n):
        if n<2:
            return 1
         else:
            return fibo(n-1) + fibo(n-2)


n=7
sum = 0
for i in range(1, n):
    sum +=  fibo(i)
    print(fibo(i))

print("suma", sum)

answered Sep 24, 2018 at 22:18

Franndy Abreu's user avatar

Considering the start of the Fibonacci series with 1 rather than 0.

def fib(no_of_elements):
    elements, start = [], 1
    while start <= no_of_elements:
        if start in [1, 2]:
            elements.append(1)
        elif start >= 3:
            elements.append(elements[start-2]+elements[start-3])
        start += 1
    return elements, sum(elements)

print(fib(8)) 

Output:
([1, 1, 2, 3, 5, 8, 13, 21], 54)

answered Nov 25, 2022 at 13:18

Alankrith G's user avatar

I found this task here.

Given the ith (1<=i<=35) Fibonacci
number F(i) calculate the sum of the
ith till i+9th number
F(i)+F(i+1)+…+F(i+9) and the last
digit of the i+246th one F(i+246)

I have been trying to solve this using python and some tricks(Binnet’s formula and a tricky recurrence):

 f=lambda n:((1+5**.5)**n-(1-5**.5)**n)/(2**n*5**.5)
 exec"n=input();print int(55*f(n)+88*f(n+1)+f(n+6)%10);"*input()

but I didn’t yet managed to squeeze thought the give source code limit which is 111 and mine is 115,any hints how to improve my solution?

I am a rather newbie to python so any sort of help resulting in a successful solution will be much appreciated.

Thanks,

asked Apr 6, 2011 at 11:49

Quixotic's user avatar

QuixoticQuixotic

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2

answered Apr 6, 2011 at 12:36

Landei's user avatar

LandeiLandei

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f = lambda n,t=5**.5:((1+t)**n-(1-t)**n)/(2**n*t) etc. spends 8 characters ,t=5**.5 to gain 12: three lots of 5**.5 -> t. That’s a saving of 4 characters, which seems to be what you require.

[EDITED to correct a typo; I had 2*n instead of 2**n in the denominator.]

You can save a few more characters with a different twist on Binet’s formula: f=lambda n:round((1+5**.5)**n/5**.5/2**n).

answered Apr 6, 2011 at 12:28

Gareth McCaughan's user avatar

Gareth McCaughanGareth McCaughan

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Here is the 110 solution, I had to rewrite the formula though and used @Gareth’s suggestion:

p=5**.5
f=lambda n:((1+p)**n-(1-p)**n)/(2**n*p)
exec "n=input();print int(f(n+11)-f(n+1)+f(n+6)%10);"*input()

Saving another symbol, 109 now (manipulating with n and getting rid of +11):

p=5**.5
f=lambda n:((1+p)**n-(1-p)**n)/(2**n*p)
exec "n=input()+6;print int(f(n+5)-f(n-5)+f(n)%10);"*input()

Edit: New way to calculate particular number, saves another 4 symbols and allows to avoid int():

def f(n):exec"a=b=1;"+"a,b=b,a+b;"*(n-1);return a
exec "n=input()+6;print f(n+5)-f(n-5)+f(n)%10;"*input()

answered Apr 6, 2011 at 13:43

zindel's user avatar

zindelzindel

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p=5**.5
f=lambda n:((1+p)**n-(1-p)**n)/(2**n*p)
exec"n=input();print 55*f(n)+88*f(n+1)+f(n+6)%10;"*input()

106 chars as long you don’t care about int() function and accept a float

answered Apr 6, 2011 at 12:55

neurino's user avatar

neurinoneurino

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Sorry I did not read your question properly before posting. I am glad you at least found some use in it.


I don’t know Python, but in Mathematica, as generic as possible:

f[1] = 1;
f[2] = 1;
f[x_] := f[x] = f[x - 1] + f[x - 2]

t = 0;

n = 35;

For[i = 0, i <= 9, i++, t += f[n + i]]

t += f[n + 246] ~Mod~ 10

Or, in terse Mathematica, still without using Fibonacci function:

f[1|2]=1;a:f@x_:=a=f[x-1]+f[x-2];Sum[f[#+x],{x,0,9}]+f[#+246]~Mod~10&

answered Apr 6, 2011 at 12:30

Mr.Wizard's user avatar

Mr.WizardMr.Wizard

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3

This one prints the Fibonacci series up to n.

def fib(n):    
    a, b = 0, 1
    while a < n:
        print(a, end=' ')
        a, b = b, a+b
        print()

Nikolay Fominyh's user avatar

answered Oct 5, 2011 at 21:14

yokmp's user avatar

yokmpyokmp

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1

What is the Fibonacci Series?

According to Google Fibonacci Series is a series of numbers

in which each number ( Fibonacci number ) is the sum of the two preceding numbers. The simplest is the series 1, 1, 2, 3, 5, 8, etc.

The Fibonacci Sequence is the series of numbers:

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, …

The next number is found by adding up the two numbers before it.

  • The 2 is found by adding the two numbers before it (1+1)
  • The 3 is found by adding the two numbers before it (1+2),
  • And the 5 is (2+3),
  • and so on!

It is that simple!

Here is a longer list:

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946, 17711, 28657, 46368, 75025, 121393, 196418, 317811, …

Can you figure out the next few numbers?

History

The Fibonacci sequence appears in Indian mathematics in connection with Sanskrit prosody, as pointed out by Parmanand Singh in 1985.[8][10][11] In the Sanskrit poetic tradition, there was interest in enumerating all patterns of long (L) syllables of 2 units duration, juxtaposed with short (S) syllables of 1 unit duration. Counting the different patterns of successive L and S with a given total duration results in the Fibonacci numbers: the number of patterns of duration m units is Fm + 1.[9]

Knowledge of the Fibonacci sequence was expressed as early as Pingala (c. 450 BC–200 BC). Singh cites Pingala’s cryptic formula misrau cha (“the two are mixed”) and scholars who interpret it in context as saying that the number of patterns for m beats (Fm+1) is obtained by adding one [S] to the Fm cases and one [L] to the Fm−1 cases. Bharata Muni also expresses knowledge of the sequence in the Natya Shastra (c. 100 BC–c. 350 AD). However, the clearest exposition of the sequence arises in the work of Virahanka (c. 700 AD), whose own work is lost, but is available in a quotation by Gopala (c. 1135)

Leonardo Pisano Bogollo Fibonacci Man

About Fibonacci The Man

His real name was Leonardo Pisano Bogollo, and he lived between 1170 and 1250 in Italy.

“Fibonacci” was his nickname, which roughly means “Son of Bonacci”.

As well as being famous for the Fibonacci Sequence, he helped spread Hindu-Arabic Numerals (like our present numbers 0,1,2,3,4,5,6,7,8,9) through Europe in place of Roman Numerals (I, II, III, IV, V, etc). That has saved us all a lot of trouble! Thank you, Leonardo.

Also Read: How Instagram Is Using Django And Python

Fibonacci Day is November 23rd, as it has the digits “1, 1, 2, 3” which is part of the sequence. So next Nov 23 let everyone know!

The Rule for Fibonacci Series

The Fibonacci Sequence can be written as a “Rule”

First, the terms are numbered from 0 onwards like this:

n = 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
xn = 0 1 1 2 3 5 8 13 21 34 55 89 144 233 377

So term number 6 is called x6 (which equals 8).

Example: the 8th term is
the 7th term plus the 6th term:
x8 = x7 + x6

So we can write the rule:

The Rule is xn = xn-1 + xn-2

where:

  • Here xn is term number “n”
  • xn-1 is the previous term (n-1)
  • And xn-2 is the term before that (n-2)

Python Program for Fibonacci Series/ Sequence

Python Program for Fibonacci Series using Iterative Approach

This approach is based on the following algorithm
1. Declare two variables representing two terms of the series. Initialize them to 0 and 1 as the first and second terms of the series respectively.
2. Initialize a variable representing loop counter to 0.
3. Loop from 0 to the total number of terms in the series.
4. In every iteration,
A. add the variables defined in step 1. This represents a term(or item) of the Fibonacci series.
B. assign the value of the second variable to first and the sum in above step A to the second variable.
So Python program to generate Fibonacci series written as per the above algorithm follows.

def fibonacci(num):
    num1 = 0
    num2 = 1
    series = 0
    for i in range(num):
        print(series, end=' ');
        num1 = num2;
        num2 = series;
        series = num1 + num2;


# running function after takking user input
num = int(input('Enter how many numbers needed in Fibonacci series- '))
fibonacci(num)

Thus the Output of the Execution is:

Enter how many numbers needed in Fibonacci series
6
0,1,1,2,3,5,

Python Program for Fibonacci Series using recursion

Create a recursive function which receives an integer as an argument. This integer argument represents the position in Fibonacci series and returns the value at that position. Thus, if it receives 5, it returns the value at 5th position in Fibonacci series.
This recursive function returns 0 and 1 if the argument value is 0 or 1. For all other values, it calls itself with the sum of nth and (n-1)th positions.
The program reads the total number of elements in Fibonacci series from the keyboard. It then initiates a loop starting from 0 till this input value. In every iteration, the recursive function is called and the resultant Fibonacci item for that position is printed.

def fibonacci(number):
    # return 0 and 1 for first and second terms
    if number == 0:
        return 0
    elif number == 1:
        return 1
    else:
        # return the sum of two numbers
        return fibonacci(number - 1) + fibonacci(number - 2)
 
# read the total number of items in Fibonacci series
max_item_input = input("Enter the number of items in Fibonacci seriesn")
max_item = int(max_item_input)
 
# iterate from 0 till number of terms
for count in range(max_item):
    print(fibonacci(count), end=",")

Thus the output of the above execution is

Enter the number of items in Fibonacci series
8
0,1,1,2,3,5,8,13,

Applications of Fibonacci Series / Sequence / Number

  • First of all the Fibonacci numbers are important in the computational run-time analysis of Euclid’s algorithm to determine the greatest common divisor of two integers: the worst case input for this algorithm is a pair of consecutive Fibonacci numbers.
  • The Fibonacci numbers are also an example of a complete sequence. So, this means that every positive integer can be written as a sum of Fibonacci numbers, where anyone number is used once at most.
  • Fibonacci numbers are used by some pseudorandom number generators.
  • They are also used in planning poker, which is a step in estimating software development projects that use the Scrum methodology.
  • Also, Fibonacci numbers arise in the analysis of the Fibonacci heap data structure.
  • Retracement of Fibonacci levels is widely used in technical analysis for financial market trading.

So, I hope you liked this article and if you have any questions/recommendations or just want to say hi, comment below!

Watch Now This tutorial has a related video course created by the Real Python team. Watch it together with the written tutorial to deepen your understanding: Exploring the Fibonacci Sequence With Python

The Fibonacci sequence is a pretty famous sequence of integer numbers. The sequence comes up naturally in many problems and has a nice recursive definition. Learning how to generate it is an essential step in the pragmatic programmer’s journey toward mastering recursion. In this tutorial, you’ll focus on learning what the Fibonacci sequence is and how to generate it using Python.

In this tutorial, you’ll learn how to:

  • Generate the Fibonacci sequence using a recursive algorithm
  • Optimize the recursive Fibonacci algorithm using memoization
  • Generate the Fibonacci sequence using an iterative algorithm

To get the most out of this tutorial, you should know the basics of Big O notation, object-oriented programming, Python’s special methods, conditional statements, functions, and basic data structures like lists, queues, and stacks. Having some familiarity with these concepts will greatly help you understand the new ones you’ll be exploring in this tutorial.

Let’s dive right in!

Getting Started With the Fibonacci Sequence

Leonardo Fibonacci was an Italian mathematician who was able to quickly produce an answer to this question asked by Emperor Frederick II of Swabia: “How many pairs of rabbits are obtained in a year, excluding cases of death, supposing that each couple gives birth to another couple every month and that the youngest couples are able to reproduce already at the second month of life?”

The answer was the following sequence:

Fibonacci recurrence relation starting with 0

The pattern begins after the first two numbers, 0 and 1, where each number in the sequence is always the sum of the two numbers before it. Indian mathematicians had known about this sequence since the sixth century, and Fibonacci leveraged it to calculate the growth of rabbit populations.

F(n) is used to indicate the number of pairs of rabbits present in month n, so the sequence can be expressed like this:

The Fibonacci sequence described as a recurrence relation. F(0) and F(1) are defined to be 0, and the nth Fibonacci number is the sum of F(n-1) and F(n-2)

In mathematical terminology, you’d call this a recurrence relation, meaning that each term of the sequence (beyond 0 and 1) is a function of the preceding terms.

There’s also a version of the sequence where the first two numbers are both 1, like so:

Fibonacci sequence starting with 11

In this alternative version, F(0) is still implicitly 0, but you start from F(1) and F(2) instead. The algorithm remains the same because you’re always summing the previous two numbers to get the next number in the sequence.

For the purposes of this tutorial, you’ll use the version of the sequence that starts with 0.

Examining the Recursion Behind the Fibonacci Sequence

Generating the Fibonacci sequence is a classic recursive problem. Recursion is when a function refers to itself to break down the problem it’s trying to solve. In every function call, the problem becomes smaller until it reaches a base case, after which it will then return the result to each intermediate caller until it returns the final result back to the original caller.

If you wanted to calculate the F(5) Fibonacci number, you’d need to calculate its predecessors, F(4) and F(3), first. And in order to calculate F(4) and F(3), you would need to calculate their predecessors. The breakdown of F(5) into smaller subproblems would look like this:

How to calculate the fifth Fibonacci number

Each time the Fibonacci function is called, it gets broken down into two smaller subproblems because that’s how you defined the recurrence relation. When it reaches the base case of either F(0) or F(1), it can finally return a result back to its caller.

In order to calculate the fifth number in the Fibonacci sequence, you solve smaller but identical problems until you reach the base cases, where you can start returning a result:

Recursive representation of Fibonacci Sequence

The colored subproblems on this diagram represent repetitive solutions to the same problem. If you go further up the tree, you’ll find more of these repetitive solutions. This means that to generate a Fibonacci sequence recursively, you have to calculate many intermediate numbers over and over. This is one of the fundamental issues in the recursive approach to the Fibonacci sequence.

Generating the Fibonacci Sequence Recursively in Python

The most common and minimal algorithm to generate the Fibonacci sequence requires you to code a recursive function that calls itself as many times as needed until it computes the desired Fibonacci number:

>>>

>>> def fibonacci_of(n):
...     if n in {0, 1}:  # Base case
...         return n
...     return fibonacci_of(n - 1) + fibonacci_of(n - 2)  # Recursive case
...

>>> [fibonacci_of(n) for n in range(15)]
[0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377]

Inside fibonacci_of(), you first check the base case. You then return the sum of the values that results from calling the function with the two preceding values of n. The list comprehension at the end of the example generates a Fibonacci sequence with the first fifteen numbers.

This function quickly falls into the repetition issue you saw in the above section. The computation gets more and more expensive as n gets bigger. The required time grows exponentially because the function calculates many identical subproblems over and over again.

To calculate F(5), fibonacci_of() has to call itself fifteen times. To calculate F(n), the maximum depth of the call tree is n, and since each function call produces two additional function calls, the time complexity of this recursive function is O(2n).

Most of those calls are redundant because you’ve already calculated their results. F(3) appears twice, and F(2) appears three times. F(1) and F(0) are base cases, so it’s fine to call them multiple times. You may want to avoid this wasteful repetition, which is the topic of the following sections.

Optimizing the Recursive Algorithm for the Fibonacci Sequence

There are at least two techniques you can use to make the algorithm to generate the Fibonacci sequence more efficient—in other words, to make it take less time to compute. These techniques ensure that you don’t keep computing the same values over and over again, which is what made the original algorithm so inefficient. They’re called memoization and iteration.

Memoizing the Recursive Algorithm

As you saw in the code above, the Fibonacci function calls itself several times with the same input. Instead of a new call every time, you can store the results of previous calls in something like a memory cache. You can use a Python list to store the results of previous computations. This technique is called memoization.

Memoization speeds up the execution of expensive recursive functions by storing previously calculated results in a cache. This way, when the same input occurs again, the function just has to look up the corresponding result and return it without having to run the computation again. You can refer to these results as cached or memoized:

Fibonacci sequence using memoization

With memoization, you just have to traverse up the call tree of depth n once after returning from the base case, as you retrieve all the previously calculated values highlighted in yellow, F(2) and F(3), from the cache earlier.

The orange path shows that no input to the Fibonacci function is called more than once. This significantly reduces the time complexity of the algorithm from exponential O(2n) to linear O(n).

Even for the base cases, you can replace calling F(0) and F(1) with just retrieving the values directly from the cache at indices 0 and 1, so you end up calling the function just six times instead of fifteen!

Here’s a possible translation of this optimization into Python code:

>>>

>>> cache = {0: 0, 1: 1}

>>> def fibonacci_of(n):
...     if n in cache:  # Base case
...         return cache[n]
...     # Compute and cache the Fibonacci number
...     cache[n] = fibonacci_of(n - 1) + fibonacci_of(n - 2)  # Recursive case
...     return cache[n]

>>> [fibonacci_of(n) for n in range(15)]
[0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377]

In this example, you use a Python dictionary to cache the computed Fibonacci numbers. Initially, cache contains the starting values of the Fibonacci sequence, 0 and 1. Inside the function, you first check if the Fibonacci number for the current input value of n is already in cache. If so, then you return the number at hand.

If there is no Fibonacci number for the current value of n, then you compute it by calling fibonacci_of() recursively and updating cache. The final step is to return the requested Fibonacci number.

Exploring an Iterative Algorithm

What if you don’t even have to call the recursive Fibonacci function at all? You can actually use an iterative algorithm to compute the number at position n in the Fibonacci sequence.

You know that the first two numbers in the sequence are 0 and 1 and that each subsequent number in the sequence is the sum of its previous two predecessors. So, you can just create a loop that adds the previous two numbers, n - 1 and n - 2, together to find the number at position n in the sequence.

The bolded purple numbers in the diagram below represent the new numbers that need to be calculated and added to cache in each iterative step:

Iterative representation of Fibonacci Sequence

To calculate the Fibonacci number at position n, you store the first two numbers of the sequence, 0 and 1, in cache. Then, calculate the next numbers consecutively until you can return cache[n].

Generating the Fibonacci Sequence in Python

Now that you know the basics of how to generate the Fibonacci sequence, it’s time to go deeper and further explore the different ways to implement the underlying algorithm in Python. In the following sections, you’ll explore how to implement different algorithms to generate the Fibonacci sequence using recursion, Python object-oriented programming, and also iteration.

Using Recursion and a Python Class

Your first approach to generating the Fibonacci sequence will use a Python class and recursion. An advantage of using the class over the memoized recursive function you saw before is that a class keeps state and behavior (encapsulation) together within the same object. In the function example, however, cache is a completely separate object, so you don’t have control over it.

Below is the code that implements your class-based solution:

 1# fibonacci_class.py
 2
 3class Fibonacci:
 4    def __init__(self):
 5        self.cache = [0, 1]
 6
 7    def __call__(self, n):
 8        # Validate the value of n
 9        if not (isinstance(n, int) and n >= 0):
10            raise ValueError(f'Positive integer number expected, got "{n}"')
11
12        # Check for computed Fibonacci numbers
13        if n < len(self.cache):
14            return self.cache[n]
15        else:
16            # Compute and cache the requested Fibonacci number
17            fib_number = self(n - 1) + self(n - 2)
18            self.cache.append(fib_number)
19
20        return self.cache[n]

Here’s a breakdown of what’s happening in the code:

  • Line 3 defines the Fibonacci class.

  • Line 4 defines the class initializer, .__init__(). It’s a special method that you can use to initialize your class instances. Special methods are sometimes referred to as dunder methods, short for double underscore methods.

  • Line 5 creates the .cache instance attribute, which means that whenever you create a Fibonacci object, there will be a cache for it. This attribute initially contains the first numbers in the Fibonacci sequence.

  • Line 7 defines another special method, .__call__(). This method turns the instances of Fibonacci into callable objects.

  • Lines 9 and 10 validate the value of n by using a conditional statement. If n is not a positive integer number, then the method raises a ValueError.

  • Line 13 defines a conditional statement to check for those Fibonacci numbers that were already calculated and are available in .cache. If the number at index n is already in .cache, then line 14 returns it. Otherwise, line 17 computes the number, and line 18 appends it to .cache so you don’t have to compute it again.

  • Line 20 returns the requested Fibonacci number.

To try this code, go ahead and save it into fibonacci_class.py. Then run this code in your interactive shell:

>>>

>>> from fibonacci_class import Fibonacci

>>> fibonacci_of = Fibonacci()

>>> fibonacci_of(5)
5
>>> fibonacci_of(6)
8
>>> fibonacci_of(7)
13

>>> [fibonacci_of(n) for n in range(15)]
[0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377]

Here, you create and then call an instance of the Fibonacci class named fibonacci_of. The first call uses 5 as an argument and returns 5, which is the sixth Fibonacci number because you’re using zero-based indices.

This implementation of the Fibonacci sequence algorithm is quite efficient. Once you have an instance of the class, the .cache attribute holds the already computed numbers from call to call.

Visualizing the Memoized Fibonacci Sequence Algorithm

You can effectively understand how each call to a recursive Fibonacci function is handled using a call stack representation. The way each call is pushed onto the stack and popped off reflects exactly how the program runs. It clearly demonstrates how calculating large numbers will take a long time if you don’t optimize the algorithm.

In a call stack, whenever a function returns a result, a stack frame representing the function call is popped off the stack. Whenever you call a function, you add a new stack frame to the top of the stack. In general, this operation has a space complexity of O(n) because there are no more than n stack frames on the call stack at a single time.

To visualize the memoized recursive Fibonacci algorithm, you’ll use a set of diagrams representing the call stack. The step number is indicated by the blue label below each call stack.

Say you want to compute F(5). To do this, you push the first call to the function onto the call stack:

First step in fib(5)

To compute F(5), you must compute F(4) as outlined by the Fibonacci recurrence relation, so you add that new function call to the stack:

Second step in fib(5)

To compute F(4), you must compute F(3), so you add another function call to the stack:

Third step in Fib(5)

To compute F(3), you must compute F(2), so you add yet another function call to the call stack:

Fourth step in fib(5)

To compute F(2), you must compute F(1), so you add that to the stack. As F(1) is a base case, it returns immediately with 1, and you remove this call from the stack:

Fifth step in fib(5)

Now you start to unwind the results recursively. F(1) returns the result back to its calling function, F(2). To compute F(2), you also need to compute F(0):

Sixth step in fib(5)

You add F(0) to the stack. Since F(0) is a base case, it returns immediately, giving you 0. Now you can remove it from the call stack:

Seventh step in fib(5)

This result of calling F(0) is returned to F(2). Now you have what you need to compute F(2) and remove it from the stack:

Eighth step in fib(5)

The result of F(2) is returned to its caller, F(3). F(3) also needs the results of F(1) to complete its calculation, so you add it back to the stack:

Ninth step in fib(5)

F(1) is a base case and its value is available in the cache, so you can return the result immediately and remove F(1) from the stack:

Tenth step in fib(5)

You can complete the calculation for F(3), which is 2:

Eleventh step in fib(5)

You remove F(3) from the stack after completing its calculation and return the result to its caller, F(4). F(4) also needs the result of F(2) to compute its value:

Twelfth step in fib(5)

You push the call to F(2) onto the stack. This is where the nifty cache comes in. You have calculated it before, so you can just retrieve the value from the cache, avoiding a recursive call to compute the result of F(2) again. The cache returns 1, and you remove F(2) from the stack:

Thirteenth step in fib(5)

F(2) is returned to its caller, and now F(4) has all it needs to compute its value, which is 3:

Fourteenth step in fib(5)

Next, you remove F(4) from the stack and return its result to the final and original caller, F(5):

Fifteenth step in fib(5)

F(5) now has the result of F(4) and also the result of F(3). You push an F(3) call onto the stack, and the nifty cache comes into play again. You previously calculated F(3), so all you need to do is retrieve it from the cache. There’s no recursive process to compute F(3). It returns 2, and you remove F(3) from the stack:

Sixteenth step in fib(5)

Now F(5) has all the values it needs to calculate its own value. You get 5 by adding 3 and 2, and that’s the final step before you pop the F(5) call off the stack. This action ends your sequence of recursive function calls:

Seventeenth step in fib(5)

The call stack is empty now. You’ve completed the final step to compute F(5):

Eighteenth step in fib(5)

Representing recursive function calls using a call stack diagram helps you understand all the work that takes place behind the scenes. It also allows you to see how many resources a recursive function can take up.

Putting all these diagrams together allows you to visualize how the whole process looks:

Visualizing the Fibonacci Sequence with Memoization Using a Call Stack

You can click the image above to zoom in on individual steps. If you don’t cache previously computed Fibonacci numbers, some of the stack stages in this diagram would be way taller, which means that they would take longer to return a result to their respective callers.

Using Iteration and a Python Function

The example in the previous sections implements a recursive solution that uses memoization as an optimization strategy. In this section, you’ll code a function that uses iteration. The code below implements an iterative version of your Fibonacci sequence algorithm:

 1# fibonacci_func.py
 2
 3def fibonacci_of(n):
 4    # Validate the value of n
 5    if not (isinstance(n, int) and n >= 0):
 6        raise ValueError(f'Positive integer number expected, got "{n}"')
 7
 8    # Handle the base cases
 9    if n in {0, 1}:
10        return n
11
12    previous, fib_number = 0, 1
13    for _ in range(2, n + 1):
14        # Compute the next Fibonacci number, remember the previous one
15        previous, fib_number = fib_number, previous + fib_number
16
17    return fib_number

Now, instead of using recursion in fibonacci_of(), you’re using iteration. This implementation of the Fibonacci sequence algorithm runs in O(n) linear time. Here’s a breakdown of the code:

  • Line 3 defines fibonacci_of(), which takes a positive integer, n, as an argument.

  • Lines 5 and 6 perform the usual validation of n.

  • Lines 9 and 10 handle the base cases where n is either 0 or 1.

  • Line 12 defines two local variables, previous and fib_number, and initializes them with the first two numbers in the Fibonacci sequence.

  • Line 13 starts a for loop that iterates from 2 to n + 1. The loop uses an underscore (_) for the loop variable because it’s a throwaway variable and you won’t be using this value in the code.

  • Line 15 computes the next Fibonacci number in the sequence and remembers the previous one.

  • Line 17 returns the requested Fibonacci number.

To give this code a try, get back to your interactive session and run the following code:

>>>

>>> from fibonacci_func import fibonacci_of

>>> fibonacci_of(5)
5
>>> fibonacci_of(6)
8
>>> fibonacci_of(7)
13

>>> [fibonacci_of(n) for n in range(15)]
[0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377]

This implementation of fibonacci_of() is quite minimal. It uses iterable unpacking to compute the Fibonacci numbers during the loops, which is quite efficient memory-wise. However, every time you call the function with a different value of n, it has to recompute the sequence over again. To fix this, you can use closures and make your function remember the already computed values between calls. Go ahead and give it a try!

Conclusion

The Fibonacci sequence can help you improve your understanding of recursion. In this tutorial, you’ve learned what the Fibonacci sequence is. You’ve also learned about some common algorithms to generate the sequence and how to translate them into Python code.

The Fibonacci sequence can be an excellent springboard and entry point into the world of recursion, which is a fundamental skill to have as a programmer.

In this tutorial, you learned how to:

  • Generate the Fibonacci sequence using a recursive algorithm
  • Optimize your recursive Fibonacci algorithm using memoization
  • Generate the Fibonacci sequence using an iterative algorithm

You’ve also visualized the memoized recursive algorithm to get a better understanding of how it works behind the scenes. To do that, you used a call stack diagram.

Once you master the concepts in this tutorial, your Python programming skills will improve along with your recursive algorithmic thinking.

Watch Now This tutorial has a related video course created by the Real Python team. Watch it together with the written tutorial to deepen your understanding: Exploring the Fibonacci Sequence With Python

In this python tutorial, you will learn about the Python Fibonacci series, we will see the Python program to print Fibonacci series and also we will check:

  • fibonacci series in python
  • Python program to print fibonacci series using recursion
  • fibonacci series in python using for loop
  • Python program to print fibonacci series up to n terms
  • Python program to print fibonacci series between 0 to 50
  • Python program to print fibonacci series using iteration
  • Python program to print fibonacci series without using recursion
  • Python program to print fibonacci series until ‘n’ value using recursion
  • print fibonacci series in python using while loop
  • Python program to print fibonacci series using function
  • Program to print first 50 fibonacci numbers in python
  • Python program to print fibonacci series in python using a list
  • fibonacci series in python using function

Now, we will see python program to print fibonacci series.

  • In this example, I have used the function def fib(n)
  • We have initialized the first term to 0 and the second term to 1.
  • The for loop is used to iterate the values till the given number
  • At last, it will print fibonacci series

Example:

def fib(n):
    a = 0
    b = 1
    if n == 1:
        print(a)
    else:
        print(a)
        print(b)
        for i in range(2,n):
            c = a + b
            a = b
            b = c
            print(c)
fib(10)

To get the output, I have used print(c) to get the Fibonacci series. You can refer to the below screenshot for the output.

Python program to print fibonacci series
Python program to print fibonacci series

The above code, we can use to print fibonacci series in Python.

You may like, How to create a variable in python and Comment lines in Python.

Python program to print fibonacci series using recursion

Here, we will see python program to print fibonacci series using recursion.

  • In this example, I have used the function def Fibonacci(number)
  • Here, if (number == 0) check whether the given number is 0 or not. If it is true, the function returns the value zero.
  • elif (number == 1) check whether the given number is 1 or not. If it is true, the function returns the value one.
  • A recursive function Fibonacci() is used to calculate the n term sequence.
  • A for loop is used to iterate and calculate each term recursively.
  • We will take the input from the user

Example:

def Fibonacci(number):
           if(number == 0):
                      return 0
           elif(number == 1):
                      return 1
           else:
                      return (Fibonacci(number - 2)+ Fibonacci(number - 1))
number = int(input("Enter the Range Number: "))
for n in range(0, number):
           print(Fibonacci(n))

To get the output, I have used print(Fibonacci(n)) to get the fibonacci series using recursion. You can refer to the below screenshot for the output.

Python program to print fibonacci series using recursion
fibonacci series in python using recursion

The above code we can use to print fibonacci series using recursion in Python.

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Fibonacci series in python using for loop

Let’s see python program to print fibonacci series using for loop

  • Firstly, we will allow the user to enter any positive integer.
  • We have initialized the First_val to 0 and the second_val to 1.
  • Here, for loop is used to iterate the number from 0 to user-specified number.
  • At last, print(next) is used to get the fibonacci series in Python

Example:

Below is an example of fibonacci series in python using for loop.

num = int(input("Enter the Range Number: "))
First_val = 0
Second_val = 1
for n in range(0, num):
           if(n <= 1):
                      next = n
           else:
                      next = First_val + Second_val
                      First_val = Second_val
                      Second_val = next
           print(next)

To get the output, I have used print(next) to get the fibonacci series using for loop. You can refer to the below screenshot for the output.

Python program to print fibonacci series using for loop
Python program to print fibonacci series using for loop

The above code, we can use to print fibonacci series using for loop in Python.

Also read, Python Program to Check Leap Year.

Python program to print fibonacci series up to n terms

Here, we will see python program to print fibonacci series up to n terms

  • Firstly, we will allow the user to enter n terms
  • We have initialized n1 to 0 and n2 to 1.
  • If the number of terms is more than 2, we will use a while loop to find the next term in the sequence by adding the preceding two terms.
  • After that, we interchange the variable and continue with the process.

Example:

n = int(input("Enter the n terms: "))
n1, n2 = 0, 1
count = 0
if n <= 0:
   print("Please enter a positive integer")
elif n == 1:
   print("Fibonacci sequence upto",n,":")
   print(n1)
else:
   print("Fibonacci sequence:")
   while count < n:
       print(n1)
       r = n1 + n2
       n1 = n2
       n2 = r
       count += 1

To get the output, I have used print(Fibonacci sequence) to get the fibonacci series up to n terms. You can refer to the below screenshot for the output

Python program to print fibonacci series up to n terms
Python program to print fibonacci series up to n terms

This is the Python program to print fibonacci series up to n terms.

Also, read, How to convert list to string in Python and Python square a number.

Python program to print fibonacci series between 0 to 50

Now, we will see python program to print fibonacci series between 0 to 50

  • We have initialized n1 to 0 and n2 to 1.
  • Every next number is found by adding up the two numbers before it.

Example:

n1,n2 = 0,1
print(n1)
while n2<50:
    print(n2)
    n1,n2 = n2, n1+n2

To get the output, I have used print to get the fibonacci series between 0 to 50. You can refer to the below screenshot for the output.

Python program to print fibonacci series between 0 to 50
Python program to print fibonacci series between 0 to 50

The above Python code, we can use to print fibonacci series between 0 to 50 in Python.

Python program to print fibonacci series using iteration

Now, we will see python program to print fibonacci series using iteration.

  • In this example, I have used the function def fib(number).
  • We have initialized first as 0 and second as 1.
  • The while loop is used to find the next term in the sequence by adding the preceding two terms.
  • And then update the value of the first and second.

Example:

def fib(number):
   count = 0
   first = 0
   second = 1
   temp = 0
   while count <= number:
      print(first)
      temp = first + second
      first = second
      second = temp
      count = count + 1
fib(6)

To get the output, I have used print to get the fibonacci series using iteration. You can refer to the below screenshot for the output.

Python program to print fibonacci series using iteration
Python program to print fibonacci series using iteration

The above Python code, we can use to print fibonacci series using iteration in Python.

You may like to read, What is a Python Dictionary and Python print without newline.

Python program to print Fibonacci series without using recursion

Let’s see python program to print fibonacci series without using recursion.

  • Firstly, the user will enter the first two numbers of the series and the number of terms to be printed from the user.
  • Then print the first two numbers
  • The while loop is used to find the sum of the first two numbers and then the fibonacci series
  • Now, print the fibonacci series till n-2 is greater than 0.

Example:

n1=int(input("Enter the first number of the series: "))
n2=int(input("Enter the second number of the series: "))
n=int(input("Enter the number of terms needed: "))
print(n1,n2,end=" ")
while(n-2):
    t=n1+n2
    n1=n2
    n2=t
    print(n2,end=" ")
    n=n-1

To get the output, I have used print to get the fibonacci series without using recursion. You can refer to the below screenshot for the output.

Python program to print fibonacci series without using recursion
Python program to print fibonacci series without using recursion

The above Python code we can use to print fibonacci series without using recursion in Python.

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Python program to print fibonacci series until ‘n’ value using recursion

Let see python program to print fibonacci series until ‘n’ value using recursion.

  • In this example, I have used the function def recursion_fib(num)
  • Here, if num <= 1 then return num
  • The other terms are obtained by adding the preceding two terms. The n term is the sum of (num-1) and (num-2) terms.
  • A recursive function recursion_fib is used to calculate the n term sequence.
  • A for loop is used to iterate and calculate each term recursively.

Example:

def recursion_fib(num):
   if num <= 1:
       return num
   else:
       return(recursion_fib(num-1) + recursion_fib(num-2))
n = 9
if n <= 0:
   print("Plese enter a positive integer")
else:
   print("Fibonacci sequence:")
   for i in range(n):
       print(recursion_fib(i))

To get the output, I have used print(recursion_fib(i)) to get the fibonacci series until ‘n’ value using recursion. You can refer to the below screenshot for the output.

Python program to print fibonacci series until 'n' value using recursion
Python program to print fibonacci series until ‘n’ value using recursion

The above code we can use to print fibonacci series until ‘n’ value using recursion in Python.

print fibonacci series in python using while loop

Now, we will see python program to print fibonacci series using while loop.

  • Firstly, the user will enter any positive integer.
  • We have initialized F_val as 0 and S_val as 1.
  • We have declared three integer variables like i, F_val, and S_val.
  • The while loop makes sure that the loop starts from 0 and is less than the user given number.
  • Within the while loop, we have used if and else.
  • And at last fibonacci series will get printed in the output.

Example:

Num = int(input("Enter the Range Number: "))
i = 0
F_val = 0
S_val = 1
while(i < Num):
           if(i <= 1):
                      Next = i
           else:
                      Next = F_val + S_val
                      F_val = S_val
                      S_val = Next
           print(Next)
           i = i + 1

To get the output, I have used print(Next) to get the fibonacci series using a while loop. You can refer to the below screenshot for the output.

Python program to print fibonacci series using while loop
Python program to print fibonacci series using while loop

The above code, we can use to print fibonacci series using while loop in Python.

Also read, Python For Loop with Examples and Python While Loop Example.

fibonacci series in python using function

Here, we will see python program to print fibonacci series using function

  • In this example, we have used the function as def fib(n)
  • We have initialized the n1 to 0 and n2 to 1.
  • if n == 1 then print(n1)
  • The for loop is used to iterate the values till the given number
  • At last, it will print fibonacci series

Example:

def fib_series(n):
    n1 = 0
    n2 = 1
    if n == 1:
        print(n1)
    else:
        print(n1)
        print(n2)
        for i in range(2,n):
            t = n1 + n2
            n1 = n2
            n2 = t
            print(t)
fib_series(5)

To get the output, I have used print(t) to get the fibonacci series using function. You can refer to the below screenshot for the output.

Python program to print fibonacci series using function
Python program to print fibonacci series using function

Program to print first 50 fibonacci numbers in python

Is anyone asking you to write a python program to get the fibonacci series between 0 to 50? Let’s see the program to print the first 50 fibonacci numbers in python.

  • In this example, I have used the function def FibonacciNum(n)
  • We have initialized the n1 to 0 and n2 to 1.
  • Here, if n < 1 then return
  • The for loop is used to iterate the values till the given number.
  • At last, call the function FibonacciNum(50) to get the first 50 fibonacci numbers in the output.

Example:

def FibonacciNum(n):
    n1 = 0
    n2 = 1
    if (n < 1):
        return
    print(n1, end=" ")
    for i in range(1, n):
        print(n2, end=" ")
        next = n1 + n2
        n1 = n2
        n2 = next
FibonacciNum(50)

You can refer to the below screenshot for the output of first 50 fibonacci numbers in python.

Program to print first 50 fibonacci numbers in python
Program to print first 50 fibonacci numbers in python

Python program to print fibonacci series in python using a list

Now, we will see python program to print fibonacci series in python using a list

  • Firstly, the user will enter any positive integer.
  • The for loop is used to iterate the values till the given number
  • At last, print(fib) to get the fibonacci series in the list.

Example:

n = int(input("Enter the number:"))
if n==0:
    fib=[0]
elif n==1:
    fib=[0,1]
else:
    fib=[0,1]
    for i in range(2,n):
        fib.append(fib[i-1]+fib[i-2])
print(fib)

To get the output, I have used print(fib) to get the fibonacci series using function. You can refer to the below screenshot for the output.

Python program to print fibonacci series in python using a list
Python program to print fibonacci series in python using a list

The above code we can use to to print fibonacci series using function in Python.

You may like the following tutorials:

  • How to subtract two numbers in Python
  • How to divide two numbers in Python
  • How to add two variables in Python

In this Python tutorial, we have learned about the Python program to print Fibonacci series or Fibonacci Series in Python. Also, we covered these below topics:

  • Python program to print fibonacci series
  • Fibonacci series in python using recursion
  • Python program to print fibonacci series using for loop
  • Python program to print fibonacci series up to n terms
  • Python program to print fibonacci series between 0 to 50
  • Python program to print fibonacci series using iteration
  • Fibonacci series in python without recursion
  • Python program to print fibonacci series until ‘n’ value using recursion
  • Python program to print fibonacci series using while loop
  • Python program to print fibonacci series using function
  • Program to print first 50 fibonacci numbers in python
  • Python program to print fibonacci series in python using a list

Bijay Kumar MVP

Python is one of the most popular languages in the United States of America. I have been working with Python for a long time and I have expertise in working with various libraries on Tkinter, Pandas, NumPy, Turtle, Django, Matplotlib, Tensorflow, Scipy, Scikit-Learn, etc… I have experience in working with various clients in countries like United States, Canada, United Kingdom, Australia, New Zealand, etc. Check out my profile.

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